Cannot find file path startfile python

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August undefined, 2024

WebOct 29, 2024 · os.startfile require file directory + file name (if your script not in the same directory with the files) import random import os himg = 'C:\\Users\\Vl\\Desktop\\aaaa\\himg\\' files = os.listdir (himg) d = random.choice (files) rng1 = (random.randint (0, 10)) if (rng1 % 2) == 0: os.startfile (himg + d) Share Improve this … WebDec 19, 2024 · 1 I saw a question on here somewhat like mine, but the solution there did not work. My code is: for filename in os.scandir ('\\\\network_drive\\folder\\folder\\folder\\'): …

python - FileNotFoundError: [WinError 2] The system cannot find …

WebJan 16, 2013 · If this is a Python 3 & unicode problem, I suggest trying to fix the string first: path = "\\\\myshare\folder" path = bytes (path, "utf-8").decode ("unicode_escape") print … WebDec 30, 2024 · import os def find_files (filename, search_path): for root, dir, files in os.walk (search_path): if filename in files: return os.path.join (root, filename) find = find_files ("Among Us.exe","D:") os.startfile (find) Share Improve this answer Follow edited Dec 30, 2024 at 4:09 answered Dec 30, 2024 at 4:04 Delupara 349 1 4 9 Add a comment crypto profit spreadsheet

python - startfile" filepath should be string, bytes or …

WebApr 4, 2024 · os.startfile () path in python with numbers Ask Question Asked 6 years ago Modified 6 years ago Viewed 9k times 1 I am working on a little project in python for work. It involves opening a file with the os.startfile () And there in lies my problem : the path to the file contains several numbers. WebJan 30, 2024 · In python, we use the method os.startfile () to start or open the file. To use this method, we pass a parameter to the method in string data type, which shows a valid … WebOct 31, 2014 · Create a batch file sam_ple.bat with the following commands and arguments cd C:\test\ start sample.exe -color Then put sam_ple.bat in the same directory as your script.py file Enter the following line of code in python to launch the exe: os.startfile ('.\sam_ple.bat') Share Improve this answer edited Nov 1, 2024 at 4:21 Michael M. 8,845 … crypto profit loss tracker

python - Retrieving contents from a directory on a network drive ...

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WebNov 4, 2024 · I know it only fails because the text file is on the server and not on the computer but I have no idea how to access it. Here's my code : from os import startfile … WebFeb 22, 2024 · You can use glob.glob() to find files using wildcard instead of listing all the files and then go through the file list to find the required files. Also there is no xdg-open in Windows platform, use os.startfile() instead of subprocess.call(). cryro the medicationWebOct 30, 2013 · There are lots of alternatives to fix this, starting with doubling the backslash: os.path.join is the safest and most portable choice. As long as you have "c:" hardcoded … cryromax beach towel

"WebApr 10, 2015 · Use GetShortPathName from kernel32.dll and access the file in this way. That is nice, but I cannot use it, since I need to use the paths in a way shutil.rmtree … " - Cannot find file path startfile python

Cannot find file path startfile python

python - startfile" filepath should be string, bytes or …

WebJun 2, 2024 · The system cannot find the file specified: 'PG2356E2-26.jpg' You are intending to operate on a path name (like "C:\PG2\356E2-26.jpg"), but are instead handing to rename () a string with all that mushed together. You didn't put any path separators in. You could do that manually, but better is to use os.path functions to form them. 1 2 3 4 5 … WebYou are using splitext to determine the source filename to rename: filename_split = os.path.splitext (filename) # filename and extensionname (extension in [1]) filename_zero = filename_split [0]# ... os.rename (filename_zero, filename_zero.replace ('+','_'))

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WebFeb 26, 2024 · #!/usr/bin/python # -*- coding: utf-8 -*- import os import enum from os import path, startfile # Enum for size units class SIZE_UNIT (enum.Enum): BYTES = 1 KB = 2 MB = 3 GB = 4 def convert_unit (size_in_bytes, unit): """ Convert the size from bytes to other units like KB, MB or GB""" if unit == SIZE_UNIT.KB: return size_in_bytes/1024 elif unit … WebOct 14, 2024 · import os file_name = raw_input("File Name: ") #file to be searched #cur_dir = raw_input("Search Directory: ") # Dir from where search starts can be replaced with …

WebDec 19, 2024 · 1 I saw a question on here somewhat like mine, but the solution there did not work. My code is: for filename in os.scandir ('\\\\network_drive\\folder\\folder\\folder\\'): print (filename) The error is: FileNotFoundError: [WinError 67] The network name cannot be found: '\\\\network_drive\\folder\\folder\\folder\\' WebYou cannot use an absolute path, unless your terminal is in that directory. Hence, you can do as in the following: import os def rename(directory): os.chdir(directory) # Changing to …

WebOct 28, 2024 · try this: import os from time import sleep os.startfile ('yourFile.xclx') sleep (4) os.system ('TASKKILL /F /IM EXCEL.EXE') # os.system ('TASKKILL /F /FI "WINDOWTITLE yourtitle"') link to the source Share Follow edited Oct 28, 2024 at 7:45 answered Oct 28, 2024 at 7:30 Matiiss 5,892 2 13 29 module 'os' has no attribute 'openfile' – Soother WebJul 19, 2024 · If os.startfile(lines_kml_flyingpath) raises FileNotFoundError, then it’s the KML file itself that can’t be found, as opposed to “open.exe” with the original subprocess …

WebJul 31, 2024 · 2 Answers Sorted by: 1 You can try os.system with open. For example: os.system ("open Untitled.pdf") This will open the file Untitled.pdf with the default PDF application ('Preview', in my case). Share Improve this answer Follow answered Jul 31, 2024 at 15:33 Roy2012 11.5k 2 22 35 it's recommended to use subprocess over …

WebJan 2, 2024 · 1. 1) Try this first. import openpyxl wb = openpyxl.load_workbook ('C:\Users\ my file location here.xlsx') type (wb) 2) else put your .py file in the same directory where … crys and tiana crypto profit taking spreadsheetWebSep 9, 2008 · It should be from path import Path then Path ('mydir/myfile.txt').abspath () – Frak Jun 5, 2024 at 14:51 1 There are no typos, you may have been using a different path module. The linked module uses a class named path. cryro in fridgeWebThe file itself is located in the same folder as the script file trying to open it: C:\Users\User\Desktop\Python stuff\Data.txt for simplicity, the simplest means to access the file (at least that I know of) is f=open These lines were coded as: f = open ("Data.txt", "r") and f = open ("C:/Users/User/Desktop/Python stuff/Data.txt", "r") crys armbrustWebJul 28, 2011 · There is no option to wait for the application to close, and no way to retrieve the application’s exit status. If you know the path of the application to open the file with, … crypto profit tax rateWebMar 11, 2012 · There is this one part of my code that causes trouble. I try to open a file using the os.system ('gnome-open ' + filePath) command but I can't get it to open a file … crys alotWebDec 7, 2024 · Python's installer doesn't define "runas" for "Python.File", but you can create it by copying the "open" command. Then you can use os.startfile to run a script elevated, as long as it doesn't require command-line arguments. If you need command-line arguments, then you'll have to use PyWin32 or ctypes to call ShellExecute [Ex] directly. – Eryk Sun cryrstal springs market bank of america